Материал: 2ИТОГ

xn 0

xk 0.8

hx 0.7

yn 0.3

yk 0.75

hy 0.45

y yn

Sz 0

P 1

zmax 100000

zmin 1000000

O

Urav augment("zmin" "zmax" "Sz" "P" )

O augment("x" "y" "z" "zmax" "zmin" "Sz" "P" )

for

x (xn hx xn)

for y (yn 0.75)

z if

x x y y

5

1

if (

x x y y

13 x x y y y if (

x x y y

13 x y 1000))

tan(x

y)

Sz Sz z

P P z

zmin if (z zmin z zmin)

zmax if (z zmax z zmax)

str augment(x y z 0 0 0 0)

O stack(O str)

strochka augment(0 0 0 zmin zmax Sz P)

O stack(O strochka)

"x"

"y"

"z"

"zmax"

"zmin"

"Sz"

"P"

0

0.3

3.233

0

0

0

0

0

0.75

1.073

0

0

0

0

O

0.7

0.3

0.642

0

0

0

0

0.7

0.75

0.121

0

0

0

0

0

0

0

0.121

3.233

5.07

0.27

#include "stdafx.h"

Начало

#include <math.h>

#include<iostream>

using namespace std;

“x“,“y“,max

int _tmain(int argc, _TCHAR* argv[])

void main()

{

double x, y, z, d, t, xn = 0.15, xk = 0.55,

x=xn

hx = 0.4, yn = 0.4, yk = 4, hy = 3;

float aa, bb, cc;

x = xn;

x<=xk

Нет Конец

y = yn;

while (x <= xk)

{

x=x+hx

y=yn

while (y <= yk)

{

d = cos(x * x * x - pow(y, 0.5));

aa = 1;

нет

bb = 3;

y<=yk

cc = aa / bb;

t = pow(x * y * y, cc);

if (t > d) z = t;

else z = d;

max=cos(x*x*x-pow(y,1/2)

cout << "x=" << x;

cout << "

y=" << y;

cout << " z=" << z << endl;

Да

z>max

Нет

y = hy + y;

x = hx + x;

}

y = yn;

z= pow(x*y*y,1/3)

z=max

}

}

x,y,z

y=y+hy

xn 0.15

xk 0.55

hx 0.4

yn 0.4

yk 4

hy 3

y yn

O

O augment("x" "y" "z" )

x xn

while

x xk

while

y yk

1

1

z

max cos x x x y

2

(x y y) 3

str augment(x y z)

O stack(O str)

y y hy

y yn

x x hx

"x"

"y"

"z"

O

0.15

0.4

0.809

O 0.15

3.4

1.201

0.55

0.4

0.893

0.55

3.4

1.853